Following is the information about some particles.
Elements | Mass number | Atomic number | Number of electrons |
P | 24 | 12 | 12 |
Q | 35 | 17 | 17 |
R | 37 | 17 | 17 |
S | 20 | 10 | 10 |
T | 23 | 11 | 10 |
V | 19 | 9 | 10 |
a)
i) Name the particle which is a metal_____
ii)Give a reason for your answer in a) i)
b)
i)Name two particles which are non metals______
ii)Give reason for your answer in b) i)
c) Name the particle which is chemically inactive and state reason for your choice.
d)Name the particle which is positively charged and state reason for your choice.
e)Name the particle which is negatively charged and state reason for your choice.
f)State the formula of the molecule formed by the union of
(i) Q only
(ii) P and Q
(iii)T and V.
Let's find out the electronic configurations of the given particles from their number of electrons.
a)
i) P
ii) P has 2 electrons in its outermost shell. It will have a tendency to give up those two electrons and attain octet. Hence P will be metal.
b)
i)Q and R
ii) Both Q and R have 7 electrons in the valence shell. Both have one electron less than a stable electronic configuration. They will have a tendency to gain one more electron to attain octet.
iii) Halogens
c) S is chemically inactive since it has a complete octet and is hence stable.
d) T is a cation or positively charged particle since the number of protons(11) is greater than the number of electrons (10).Electronic configuration of T:2,8.
e)V is an anion/negatively charged particle since the number of electrons (10) is greater than the number of protons(9).Electronic configuration of V:2,8.
f)
i) . Since Q has 7 valence electrons, it needs one more electron to complete the octet. Thus two Q atoms can share a pair of electrons and form a stable covalent molecule.
ii). P has valency 2 and Q has valency 1. Hence 2 atoms of Q and one atom of P can form a stable molecule. P will give up two electrons, each one of which is taken by Q atoms.
iii) TV .T is a uni positive cation and V is a uni negative anion, they will combine to form TV.