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Question

Following is true for stability between the two structures.

A
CH3O|CHCH2>CH3O|CHC=CHCH3
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B
CH2=CHCH=CHCH2>CHCH2||CCHCH3
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C
CH2=CH3|CCH2>CH3CH=CH2CH2
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D
None of the above
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Solution

The correct option is D CH2=CHCH=CHCH2>CHCH2||CCHCH3
In option (A), the second structure, negative charge is on an electronegative atom (oxygen) and is in conjugation with π bond. Thus the second structure is more stable.
In option (B), two π bonds are in conjugation in first structure thus it is more stable.
In option (C), a positive charge is in conjugation with π bond and thus the second structure is more stable.

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