Following reaction can take place in both direction A k 1 k 2 - B- It is given that for the forward reaction -B-Rate 0-01 M 1 - 10-2 Ms-1 0-02 M 2 - 10-2 Ms-1Hence - net reaction rate of B is -

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Standard XII

Chemistry

Rate of Reaction

Following rea...

Question

Following reaction can take place in both direction $A_{1} B$ , It is given that for the forward reaction :
[B] Rate
$0.01 M$ $1 \times 10^{- 2} M s^{- 1}$
$0.02 M$ $2 \times 10^{- 2} M s^{- 1}$
Hence , net reaction rate of B is :

k_{1}

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k_{1} - k_{2}

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k_{1} [A] - k_{2}

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none of these

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Solution

The correct option is A $k_{1}$
From the graph, it is clear that the Following reaction is a Zero Order Reaction.

So, Rate = Rate Constant = $k_{1}$

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[B]	Rate
$0.01 M$	$1 \times 10^{- 2} M s^{- 1}$
$0.02 M$	$2 \times 10^{- 2} M s^{- 1}$

Following reaction can take place in both direction Ak1⇌k2B, It is given that for the forward reaction :[B]Rate0.01M1×10−2Ms−10.02M2×10−2Ms−1Hence , net reaction rate of B is :

The correct option is A k1From the graph, it is clear that the Following reaction is a Zero Order Reaction.So, Rate = Rate Constant = k1

Following reaction can take place in both direction $A_{1} B$ , It is given that for the forward reaction :
[B] Rate
$0.01 M$ $1 \times 10^{- 2} M s^{- 1}$
$0.02 M$ $2 \times 10^{- 2} M s^{- 1}$
Hence , net reaction rate of B is :

The correct option is A $k_{1}$
From the graph, it is clear that the Following reaction is a Zero Order Reaction.

So, Rate = Rate Constant = $k_{1}$