Following Reaction,
${N H}_{4}^{+} (a q) + {C N}^{-} (a q) ⇌ H C N (a q) + {N H}_{3} (a q)$
proceeds in:

forward direction

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backward direction

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in both sides equally

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can't be predicted

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Solution

The correct option is A backward direction
This reaction will proceed in backward direction.This is because ammonia dissolves in water to form ammonium ions giving basic solution and under basic conditions hydrogen cyanide remains predominantly in cyanide ion.

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Similar questions

N H_{3} (a q) + H_{2} C O_{3} (a q) ⇋ N H_{4}^{+} (a q) + H C O_{3}^{-} (a q)

N H_{4}^{+}

N H_{3} (a q) + H_{2} C O_{3} (a q) ⟶ N H_{4}^{+} (a q) + H C O_{3}^{-} (a q), N H_{4}^{+} (a q)

H C N (a q) ⇋ H^{+} (a q) + C N^{-} (a q)

C N^{-}

N H_{3 (a q)} + H_{2} O_{(l)} = N H_{4}^{+} (a q) + O H^{-} (a q)

K_{a}

5.76 \times 10^{- 10}

4.8 \times 10^{- 10}

N H_{4}^{+}

H C N

N H_{4}^{+} (a q .) + C N^{-} (a q .) ⇌ N H_{3} (a q .) + H C N (a q .)

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