Following table represents critical temperature of some gases. Arrange these gases in their increasing order of liquefaction.

Gas $H_{2}$ $H e$ $N_{2}$ $O_{2}$

$T_{c}$ $(K)$ 33.2 5.3 126 154.3

H e < N_{2} < H_{2} < O_{2}

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H_{2} < H e < N_{2} < O_{2}

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H e < H_{2} < N_{2} < O_{2}

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O_{2} < N_{2} < H_{2} < H e

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Solution

The correct option is C $H e < H_{2} < N_{2} < O_{2}$
More will be critical temperature easier is the liquefaction of the gas. Hence, correct order will be:
$H e < H_{2} < N_{2} < O_{2}$

Suggest Corrections

Similar questions

\begin{matrix} G a s e s : & H_{2} & H e & O_{2} & N_{2} T_{C} (K) & 33.2 & 5.2 & 154.3 & 126 \end{matrix}

a

T

T

Gas	$C H_{4}$	$K r$	$N_{2}$	$C l_{2}$
$a (a t m L^{2} . m o l^{- 1})$	2.283	2.439	1.408	6.579

293 K

H e = 144.97 k b a r

H_{2} = 69.16 k b a r

N_{2} = 76.48 k b a r

O_{2} = 34.86 k b a r

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