Solution: 1 Mark each
(i) Suraj's average number of points.
Mean=Sum of all observationTotal number of observation
Mean=10+16+14+104=504
⇒Mean=12.5
(ii) To find the mean number of points per game of Harshith, mean should be divided by 3 because he played in only 3 games.
Mean=Sum of all observationTotal number of observation
Mean=13+11+83=323
⇒Mean=10.66
(iii) For Abhijit's game mean is:
Mean=Sum of all observationTotal number of observation
Mean=8+0+4+64=184
⇒Mean=4.5
(iv) Comparing everybody's mean score, Suraj has highest mean.
⇒ Suraj is best performer.