Question

For $0\le x\le \pi$, the area between the curve $y=\sin x$ and x-axis is

• A. $1squnit$
• B. $0squnit$
• C. $2squnit$
• D. $-1squnit$

Answer 1

Answer: (C)

$2squnit$

The area between $y=\sin x$ and x-axis
$={\int }_0^{\pi }ydx$
$\therefore$ Required are $={\int }_0^{\pi }\sin xdx$
$=[-\cos x{]}_0^{\pi }$
$=\left[\right(-\cos \pi )-(-\cos 0\left)\right]$
$=1+1=2squnit$.