wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For 1 M solution of HA, the dissociation constant Ka in terms of vant Hoff factor (i) can be written as :

A
(i1)2i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(i+1)2i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
i(i1)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(i1)2(2i)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C (i1)2(2i)
HAH++A
i=1+α
α=(i1)
Now, Ka=Cα21αKa=(i1)21(i1)
Ka=(i1)22i

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems for Differentiability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon