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Reactivity with Halogens and Hydrogen (Group 2)

for 100

Question

for 100 % dissociation of k4(fe(CN)6,van't Hoff factors i=5

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Solution

Dear student,
For the 100 % dissociation , the Van't Hoff factor = Total no. of ions
Now in K₄ [ Fe(CN)₆ ] there are 4 K⁺ ions and one [ Fe(CN)₆ ]^4- ion , thus total no. of ions = 5
and i = 5
Regards

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