Question

For 2.95 M ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solution, what will be the grade (strength by volume) and percentage strength?

• A. 28,10
• B. 35,12
• C. 33,10
• D. 36,12

Answer 1

The correct option is C 33,10

Volume strength of $H_2{O}_2=11.2\times$ Molarity

Volume strength $=11.2\times 2.95=33$ $V$

Since, $10$ $V$ corresponds to $3\%$ strength.

$⟹100\%$ Strength $=333$ $V$

$\%$ Strength of $33$ $V=\frac{33}{333}\times 100=10\%$