For 2 mole of an ideal gas; the relation between $C_{0}$ & $C_{1}$ (non-molar) are:

C_{0} - C_{1}

= 2R

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C_{1} - C_{0}

= 2R

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C_{0} - C_{1}

= R

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C_{1} - C_{0}

= R

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Solution

The correct option is A $C_{0} - C_{1}$ = 2R
The molar heat capacity C, at constant pressure, is represented by $C_{P}$ . At constant volume, the molar heat capacity C is represented by $C_{V}$ .
For 1 mole of an ideal gas:
$H = U + P V$
For 2 moles of an ideal gas:
$H = U + 2 P V$
differentiating on both sides
$d H = d U + d P V$
$C p d T = C v d T + 2 R d T$
dT will be cancelled
$∴ C p - C v = 2 R$

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