For 2 SO 2 g - O 2 g - 2 SO 3 g - - H is equal to-A- - U -2 RTB- - U -2 RTC- - U - RTD- - U - RT

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For 2 SO 2 g ...

Question

For $2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$ , $Δ H$ is equal to:

Δ U + 2 R T

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Δ U - 2 R T

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Δ U - R T

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Δ U + R T

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Similar questions

N_{2} (g) + 2 H_{2} (g) ⇌ 2 N H_{3} (g)

Δ H

For the reaction, N₂ + 3H₂ ⇌ 2NH₃, ∆H= …………….

C (s) + O_{2} (g) ⟶ C O_{2} (g)

Δ H = Δ U + R T

N_{2} (g) + 3 H_{2} (g) ⟶ 2 N H_{3} (g)

Δ H = Δ U

N H_{4} H S (s) ⟶ N H_{3} (g) + H_{2} S (g)

Δ H = Δ U - 2 R T

P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)

Δ H = Δ U + 2 R T

2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)

Δ H = Δ U - R T

C (s) + O_{2} (g) ⟶ C O_{2} (g)

Δ H = Δ U + R T

N_{2} (g) + 3 H_{2} (g) ⟶ 2 N H_{3} (g)

Δ H = Δ U

N H_{4} H S (s) ⟶ N H_{3} (g) + H_{2} S (g)

Δ H = Δ U - 2 R T

P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)

Δ H = Δ U + 2 R T

2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)

Δ H = Δ U - R T

2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)

Δ H

Δ U

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