For 3- 3 matrices A and B- if - B - -1 and A-2B then find - A -

The correct option is B 8 For a 3× 3 matrix we know, |kB|= k ^ 3 |B| ∴ #160; |A|=2^3|B| ∴ #160; |A|=8(1) ....... [ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Logarithmic Differentiation

For 3× 3 ma...

Question

For $3 \times 3$ matrices $A$ and $B$ , if $| B | = 1$ and $A = 2 B$ then find $| A |$ .

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $8$
For a $3 \times 3$ matrix we know,
$| k B | = k^{3} | B |$
$∴$ $| A | = 2^{3} | B |$
$∴$ $| A | = 8 (1)$ ....... [ $∵$ $| B | = 1$ ]
$∴$ $| A | = 8$

Suggest Corrections

Similar questions

Q. If

A

and

B

are two distinct matrices such that

A^{3} = B^{3}

and

A^{2} B = B^{2} A

, find

d e t (A^{2} + B^{2})

Q. For two

3 \times 3

matrices

A

and

B

, let

A + B = 2 B^{'}

and

3 A + 2 B = I_{3}

, where

B^{'}

is the transpose of B and

I_{3}

3 \times 3

identify matrix. Then :

Q. For two

3 \times 3

matrices

A

and

B,

let

A + B = 2 B^{'}

and

3 A + 2 B = I_{3},

where

B^{'}

is the transpose of

B

and

I_{3}

3 \times 3

identity matrix. Then :

Q. Matrices A and B satisfy

A B = B^{- 1}

, where

B = [\begin{matrix} 2 & - 1 2 & 0 \end{matrix}]

, then find the value of

k

for which

k A - 2 B^{- 1} + I = O

, without finding

B^{- 1}

Q. In a triangle ABC if a =13, b = 8 and c = 7, then find sin A.

Join BYJU'S Learning Program

For 3×3 matrices A and B, if |B|=1 and A=2B then find |A|.

The correct option is B 8For a 3×3 matrix we know,|kB|=k3|B|∴ |A|=23|B|∴ |A|=8(1) ....... [∵ |B|=1 ]∴ |A|=8

For $3 \times 3$ matrices $A$ and $B$ , if $| B | = 1$ and $A = 2 B$ then find $| A |$ .

The correct option is B $8$
For a $3 \times 3$ matrix we know,
$| k B | = k^{3} | B |$
$∴$ $| A | = 2^{3} | B |$
$∴$ $| A | = 8 (1)$ ....... [ $∵$ $| B | = 1$ ]
$∴$ $| A | = 8$