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For a<0, argi...

Question

For $a < 0$ , $arg (i a)$ is

A

\frac{π}{4}

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B

\frac{π}{2}

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C

π

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D

- \frac{π}{2}

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Solution

The correct option is D $- \frac{π}{2}$
For $z = i a, a < 0$
$z$ must lies on negative imaginary axis.
Hence, $arg (z) = arg (i a) = - \frac{π}{2}$

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