Question

For a $1^{st}$ order reaction, if the concentration is doubled then the rate of reaction becomes:

• A. double
• B. half
• C. four times
• D. remain same

Answer 1

The correct option is A double

For a first-order reaction, rate$=K\left[A\right]$

when the concentration of $A$ is doubled,

$Rat{e}_{new}=K\left[2A\right]$

$=2\times rate$

The rate of reaction becomes double.