Question

For a 100 ml solution of ${10}^{-2}M$ $NaOH$ the ratio $pH:pOH$ would be:

• A. $6:1$
• B. $1:6$
• C. $2:1$
• D. ${10}^{10}:1$

Answer 1

The correct option is B $1:6$

$NaOH$ undergoes complete ionisation.

So, $\left[{OH}^{-}\right]={10}^{-2}\Rightarrow \left[H^{+}\right]=\frac{{10}^{-14}}{\left[{OH}^{-}\right]}=\frac{{10}^{-14}}{{10}^{-2}}={10}^{-12}$

$pH=2$ & $pOH=12$

$\therefore$ $pH:pOH=2:12=1:6$