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Question

For a 25 cm thick cement concrete pavement, analysis of stresses gives the following values wheel load stress due to edge loading 25 kg/cm2, wheel load stress due to corner loading 30 kg/cm2, warping stress at corner region during summer 10 kg/cm2, warping stress at corner region during winter 9 kg/cm2, warping stress at edge region during summer 10 kg/cm2, warping stress at edge region during winter 7 kg/cm2, frictional stress during summer 5 kg/cm2, frictional stress during winter 3 kg/cm2. The most critical stress value for this pavement is _____kg/cm2
  1. 40

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Solution

The correct option is A 40
Thickness of cc pavement t = 25 cm

Wheel load stress due to edge loading
σe=25 kg/cm2
Wheel load stress due to corner loading
σc= 30 kg/cm2
Warping stress at corner region during summer
σw=10 kg/cm2
Warping stress at corner region during winter
σw=9 kg/cm2
Warping stress at edge region during summer
σw=10 kg/cm2
Warping stress at edge region during winter
σw=7 kg/cm2
Frictional stress during summer
σf=5 kg/cm2
Frictional stress during winter
σf=3 kg/cm2
Critical Combination of stress -
(1) During summer, mid day (at edge)
σcritical=σe+σwσf
=25+105
=30 kg/cm2

(2) winter, mid-day (at edge)
σcritical=σe+σw+σf
=25+7+3
=35 kg/cm2

(3) summer mid-night (at corner)
σcritical=σc+σw
=30+10
=40 kg/cm2

(4) winter mid-night (at corner)
σcritical=σc+σw
=30+9
=39 kg/cm2

Max (30, 35, 40, 39)=40 kg/cm2

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