For a 3 digit number abc, abc - cba is divisible by 99.
True
False
Let the 3-digit number be abc.
abc = 100a+10b+c (100a+10b+c)-(100c+10b+a) = 100a+10b+c-100c-10b-a = 99a-99c = 99(a-c)
If is a 3-digit number, then
is always divisible by
A. 12
B. 15
C. 18
D. 21