Question

For a 3d-orbital, the orbital angular momentum is

• A. $\frac{2h}{2\pi }$
• B. $Zero$
• C. $\sqrt{6}\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

The correct option is C $\sqrt{6}\frac{h}{2\pi }$

Orbital angular momentum $\sqrt{l(l+1)}\frac{h}{2\pi }$
For d orbital,l = 2
Hence orbital angular momentum $=\sqrt{6}\frac{h}{2\pi }$