For a 5 gm substance the heat supplied in cals- and temperature in -C curve is given below- Then the specific heat of substance for liquid state will be -

The correct option is B 0.2 cal/(gm^∘C Specific heat= 100cal/(5g)(100^oC)= 0.2cal/g^oC Energy= 220 120= 100 cal δ(T)= 100 0= 100^oC m= 5g ...

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Byju's Answer

Standard XII

Chemistry

Molar and Specific Heat Capacity

For a 5 gm su...

Question

For a 5 gm substance the heat supplied (in cals.) and temperature (in $^{\circ} C$ ) curve is given below. Then the specific heat of substance for liquid state will be :

1 c a l / g m^{\circ} C

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0.2 c a l / (g m^{\circ} C

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2.5 c a l / g m^{\circ} C

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Solution

The correct option is B $0.2 c a l / (g m^{\circ} C$
Specific heat= $\frac{100 c a l}{(5 g) (100^{o} C)} = 0.2 c a l / g^{o} C$
Energy= 220-120= 100 cal
$δ (T) = 100 - 0 = 100^{o} C$
m= 5g

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