The given sets are A={5,10,15,20}, B={6,10,12,18,24} and C={7,10,12,14,21,28}
Let us first find A∖(B∖C) as follows:
A∖(B∖C)={5,10,15,20}∖({6,10,12,18,24}∖{7,10,12,14,21,28})={5,10,15,20}∖{6,18,24}
={5,10,15,20}........(1)
Now we find (A∖B)∖Cas follows:
(A∖B)∖C=({5,10,15,20}∖{6,10,12,18,24})∖{7,10,12,14,21,28}={5,15,20}∖{7,10,12,14,21,28}
={5,15,20}........(2)
Since equation 1 is not equal to equation 2,
Hence, A∖(B∖C)≠(A∖B)∖C