Question

For a binomial distribution $\overline{x}=4$, ${\sigma }^2=3$ then the distribution of $x$ is

• A. ${\left(\frac{1}{4}+\frac{3}{4}\right)}^{15}$
• B. ${\left(\frac{3}{4}+\frac{1}{4}\right)}^{16}$
• C. ${\left(\frac{1}{2}+\frac{1}{4}\right)}^{16}$
• D. ${\left(\frac{1}{2}+\frac{1}{4}\right)}^8$

Answer 1

The correct option is B ${\left(\frac{3}{4}+\frac{1}{4}\right)}^{16}$

For binomial distribution probability of success p and failure q

Mean=$\surd \left(np\right)$=3

σ2=3σ2=3 =npq

And , p+q=1

Solving above equation we get n=16,p=3/4,q=1/4