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Law of Conservation of Energy

for a black b...

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for a black body at temperature 727 degrees C,its rate of energy loss is 20 W and temperature of surrounding is 227degrees C.If temperature of black body is changed to 1227 degrees C ,then its rate of energy loss will be?

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Q. For a black body at temperature

727^{o}

its rate of energy loss is

20

watt and temperature of surrounding is

227^{o} C

. If temperature of black body is changed to

1227^{C}

then its rate of energy loss will be:

Q. For a block body temperature

727^{o} C,

its rate of energy loss is

20 w a t t

and temperature of surrounding is

227^{o} C .

If temperature of black body is changed to

1227^{o} C

then its rate of energy loss will be:

Q. For a black body at a temperature of

727^{\circ} C

, Its radiated power is 60 watt and temperature of the surrounding is

227^{\circ} C

If the temperature of the black body is changed to

1227^{\circ} C

, Then its radiating power will be

Q. A black body at temperature

T

radiates energy at the rate of

E

^{- 2}

. In reducing its temperature to

T / 2

the rate of energy radiation will be

Q. A black body at a temperature of

227^{\circ} C

radiates heat energy at the rate

5 c a l / c m^{2} / s

. At a temperature of

727^{\circ} C

, the rate of heat radiated per unit area in

c a l / c m^{2}

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