Question

For a body in S.H.M. the velocity is given by the relation $v=\sqrt{144-16x^2}m/s$. The maximum acceleration is

• A. $12m/s^2$
• B. $16m/s^2$
• C. $36m/s^2$
• D. $48m/s^2$

Answer 1

Answer: (D)

$48m/s^2$

$v=\omega \sqrt{A^2-x^2}$
Comparing $\omega =4\frac{rad}{sec};A^2=9;A=3m$
$a=-{\omega }^{2}A$
$=-16\times 3=-48m/s^2$