Question

For a capacitor, distance between the plates $=d$, p.d between the plates $=V,k=1$, area of each plate $=A$ and electric field between the plates $=E$. For another capacitor distance between plates $=d$, p.d between plates $=V,k=2$, area of each plate $=2A$ and electric field between the plates $=E^1$. Relation between $E$ and $E^1$ is:

• A. $E^1=E/4$
• B. $E^1=E/2$
• C. $E^1=E$
• D. $E^1=4E$

Answer 1

The correct option is C $E^1=E$

$E=\frac{V}{d}$

where, $V-$ potential between plates

and, $d-$ distance between plates

so, no change in $V$ and $d$

$E^1=E$