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Question

For a cell reaction 2H2(g)+O2(g)2H2O(l) ;rS298=0.32 kJ/K. What is the value of fH298(H2O, l)?
Given O2(g)+4H+(aq.)+4e2H2O(l);E=1.23 V

A
285.07 kJ/mol
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B
570.14 kJ/mol
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C
285.07 kJ/mol
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D
None of these
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Solution

The correct option is C 570.14 kJ/mol
As we know,
ΔG0=nFE0=4965001.23=474.780kJ/mol
Also,
ΔG=ΔHTΔS;ΔH=474.782980.32=569.14kJ/mole

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