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Question

For a cell Terminal potential difference is 2.2V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R=5Ω. Determine internal resistance of cell (r)

A
109Ω
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B
910Ω
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C
119Ω
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D
59Ω
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Solution

The correct option is C 109Ω
Let Ri= internal resistance of the battery
Let Vo=open circuit voltage of the battery =2.2V
Let Vl= loaded voltage of the battery =1.8V
Let Rl=resistance of the load =5Ω

Vl=(Rl)×(Vo)Rl+Ri

Rl+Ri=(Rl)(Vo)Vl

Ri=Rl(VoVl1)

Ri=5(2.21.81)

Ri=109Ω

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