Question

For a certain element, electrochemical equivalent is $2.1\times {10}^{-4}g{C}^{-1}$. The element could be :

• A. $Ca$
• B. $Mg$
• C. $Al$
• D. $Ag$

Answer 1

The correct option is A $Ca$

Electrochemical equivalent, $Z=\frac{E}{F}$, where, $E=$ equivalent mass of element

$E=2.1\times {10}^{-4}\times 96500=20$ g eq/mol.

Therefore, calcium is the element as it has oxidation state $+2$ and molecular weight $40$ g/mol.

Option A is correct.