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First Order Reaction

For a certain...

Question

For a certain first order reaction, it takes $5$ minutes for the initial concentration of $0.6$ $m o l$ $L^{- 1}$ to become $0.2$ $m o l$ $L^{- 1}$ . What is the rate constant for this reaction? $(log 3 = 0.4771)$

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Solution

$t = 5 m i n$
$A o = 0.6 m o l l^{- 1}$
$A = 0.2 m o l l^{- 1}$
$K = \frac{2.303}{5} l o g (\frac{0.6}{0.2})$
$K = 0.219 {m i n}^{- 1}$

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