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Question

For a certain organ pipe, three successive resonance frequencies are observed at 425, 595 and 765, Hz respectively, Taking the speed of sound in air to be 340 m/s the fundamental frequency of the pipe(in Hz) is

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Solution

We don't know, which organ pipe is used for it , so, first of all we should take ratio of all three harmonics.

e.g., 425Hz : 595Hz : 765 Hz

5 × 85 Hz : 7 × 85Hz : 9 × 85 Hz

(2 × 2 + 1) 85Hz : (2 × 3 + 1) 85Hz : (2 × 4 + 1) 85Hz

what you saw, each the successive harmonics is an odd number.

This is possible only when organ pipe is closed .

And 85 is common for all harmonics , so fundamental frequency is 85Hz


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