Question

For a certain reaction of order 'n' the time for half change $t_{1/2}$ is given by; $t_{1/2}=\frac{2-\sqrt{2}}{K}\times c_0^{1/2}$, where K is rate constant and $c_0$ is initial concentration. The value of n is:

• A. 1
• B. 2
• C. 0
• D. 0.5

Answer 1

The correct option is D 0.5

From given expression, it can be seen that
Integrated rate expression for 1/2 order is:
$-2c^{1/2}=Kt=2c_0^{1/2}$

Thus, the order of the reaction is half and the value of n is 0.5