For a certain reaction the rate law is rate =k[C]3/2. If the rate of the reaction is 0.020 mol L−1s−1 when [C] = 1.0 M, what is the rate when [C] = 0.60 M?
A
0.0093 mol L−1s−1
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B
0.012 mol L−1s−1
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C
0.033 mol L−1s−1
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D
0.040 mol L−1s−1
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Solution
The correct option is A0.0093 mol L−1s−1 The rate law is rate =k[C]3/2
The rate of the reaction is 0.020molL−1s−1 when [C]=1.0 M. The rate law becomes 0.020molL−1s−1=k[1.0M]3/2
⇒k=0.020mol−0.5L0.5s−1 When, [C]=0.60M, the rate law is