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Question

For a certain reaction the rate law is rate =k[C]3/2. If the rate of the reaction is 0.020 mol L−1s−1 when [C] = 1.0 M, what is the rate when [C] = 0.60 M?

A
0.0093 mol L1s1
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B
0.012 mol L1s1
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C
0.033 mol L1s1
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D
0.040 mol L1s1
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Solution

The correct option is A 0.0093 mol L1s1
The rate law is rate =k[C]3/2
The rate of the reaction is 0.020molL1s1 when [C]=1.0 M.
The rate law becomes 0.020molL1s1=k[1.0M]3/2
k=0.020mol0.5L0.5s1
When, [C]=0.60M, the rate law is
Rate =k[C]3/2
Rate =(0.020mol0.5L0.5s1)×[0.60M]3/2
Rate =0.0093molL1s1

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