Question

For a certain reaction the variation of the rate constant with temperature is given by the equation
$ln{k}_t-ln{k}_0=\frac{\left(ln3\right)t}{10}(t\ge 0^{o}C)$
The value of the temperature coefficient of the reaction is:

• A. 0.1
• B. 1
• C. 10
• D. 3

Answer 1

The correct option is D 3

$\frac{k_t}{k_0}=(\mu {)}^{t-0/10}$ ------- 1

Taking log gives $lo{g}_e{k}_1-lo{g}_e{k}_0=\frac{t}{10}lo{g}_e\left(\mu \right)$

$\Rightarrow ln{k}_1=ln{k}_0+\left(\frac{ln\left(\mu \right)}{10}\right)t$

Comparison indicates $\frac{ln\left(\mu \right)}{10}=\frac{ln3}{10}\Rightarrow \mu =3$