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Standard XII

Chemistry

Order of Reaction

For a certain...

Question

For a certain reaction, xM $⟶$ yL, the rate of reaction increases by 4 times when the concentration of M is doubled. The rate law is :

rate = k

{[M]}^{2}

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rate = k

{[M]}^{1}

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rate = k

{[M]}^{- 2}

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none of these

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Solution

The correct option is A rate = k ${[M]}^{2}$
For a certain reaction, xM $⟶$ yL, the rate of reaction increases by $4$ times when the concentration of M is doubled.
Now, $4 = 2^{2}$
This indicates that the order of the reaction with respect to M is $2$ .
The rate law is rate $= k$ ${[M]}^{2}$ .

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For a certain reaction, xM ⟶ yL, the rate of reaction increases by 4 times when the concentration of M is doubled. The rate law is :

The correct option is A rate = k [M]2For a certain reaction, xM ⟶ yL, the rate of reaction increases by 4 times when the concentration of M is doubled. Now, 4=22This indicates that the order of the reaction with respect to M is 2.The rate law is rate =k [M]2.

For a certain reaction, xM $⟶$ yL, the rate of reaction increases by 4 times when the concentration of M is doubled. The rate law is :

The correct option is A rate = k ${[M]}^{2}$
For a certain reaction, xM $⟶$ yL, the rate of reaction increases by $4$ times when the concentration of M is doubled.
Now, $4 = 2^{2}$
This indicates that the order of the reaction with respect to M is $2$ .
The rate law is rate $= k$ ${[M]}^{2}$ .