For a certain sample it took 20 minutes for 200 ml to percolate. So what will be the rate of percolation?

\frac{1}{10}

ml/min

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110 mL / min

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10 mL/ min

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200 ml /min

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Solution

The correct option is C 10 mL/ min
Rate of percolation = $\frac{200 m l}{20 m i n}$
So, the correct answer is '10mL/min

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For a certain sample it took 20 minutes for 200 ml to percolate. So what will be the rate of percolation?

The correct option is C 10 mL/ minRate of percolation = 200ml20minSo, the correct answer is '10mL/min

The correct option is C 10 mL/ min
Rate of percolation = $\frac{200 m l}{20 m i n}$
So, the correct answer is '10mL/min