Question

For a chemical reaction 2X + Y $\to$ Z, the rate of appearance of Z is 0.05 mol $L^{-1}mi{n}^{-1}$. The rate of disappearance of X will be:

• A. 0.05 mol $L^{-1}h{r}^{-1}$
• B. 0.05 mol $L^{-1}mi{n}^{-1}$
• C. 0.1 mol $L^{-1}mi{n}^{-1}$
• D. 0.25 mol $L^{-1}mi{n}^{-1}$

Answer 1

Answer: (C)

0.1 mol $L^{-1}mi{n}^{-1}$

2X + Y $\to$ Z
Rate = $\frac{-d\left[X\right]}{2dt}=\frac{-d\left[Y\right]}{dt}=\frac{+d\left[Z\right]}{dt}$
$\frac{-d\left[X\right]}{2dt}=2\times \frac{d\left[Z\right]}{dt}$ = 2 $\times$ 0.05 = 0.1 mol $L^{-1}mi{n}^{-1}$