Question

# For a chemical reaction $$A+3B\rightarrow Product$$, it was observed that the rate of reaction increases nine times when the concentration of B increased three times by keeping the concentration of A as constant. On doubling the concentration of both rate increases eight times. Differential rate equation can be given as:

A
r=k[A][B]3
B
r=k[A][B]2
C
r=k[A]2[B]
D
r=k[A]2[B]13

Solution

## The correct option is B $$r=k[A][B]^2$$According to question,$$rate=k[A]^m[B]^n$$ ------ 1 $$rate_1=9 rate=k[A]^m [3B]^n$$ ----------- 2$$rate_2=8 rate=k[2A]^m [2B]^n$$ --------- 3From 1 and 2 equation we get, $$n=2.$$From 1 and 3 equation after substituting $$n$$ value we get, $$m=1.$$Hence $$m=1, n=2$$.Option B is correct.ChemistryNCERTStandard XII

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