Question

For a chemical reaction, $A⟶E$, it is found that rate of reaction is doubled when the concentration of $A$ is increased four times. The order of the reaction is:

• A. $1$
• B. $2$
• C. $1/2$
• D. $0$

Answer 1

The correct option is C $1/2$

${\vartheta }_{old}=k{\left[A\right]}^n,{\vartheta }_{new}=k{\left[4A\right]}^n\frac{{\vartheta }_{new}}{{\vartheta }_{old}}=2=4^{n}n=\frac{1}{2}$