Question

For a chemical reaction, $A\to B$, it is observed that the rate of reaction doubles when the concentration of $A$ is increased four times. The order of reactions in $A$ is :

• A. Two
• B. One
• C. Half
• D. Zero

Answer 1

The correct option is C Half

Here the answer is wrong, and the correct answer is an option(C).

$A........\to Product$

Rate = $K$[$concentrationofA$]${}^x$.................(1)

$2\times rate$ $=K[4\times concentrationofA]$${}^x$..........................(II)

$÷$ (1) by (II)

$\frac{1}{2}=\frac{1}{4^x}$

$\Rightarrow 2x=1$

$x=\frac{1}{2}$

Hence, the answer is $x=\frac{1}{2}$ (Half)