Question

For a chemical reaction $A\to F,$ it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is:

• A. 2
• B. 1
• C. 1/2
• D. Zero

Answer 1

Answer: (C)

1/2

$r_1=k[A{]}^n$
$r_2=2r_1=k[4A{]}^n$
$\frac{2r_1}{r_1}=(4{)}^n$
$(2{)}^1=(2{)}^{2n}$
$n=\frac{1}{2}$