Question

For a chemical reaction A $\to$ Products, the rate of reaction doubles when the concentration of A is increased by 4 times.
The order of reaction is:

• A. 4
• B. 0
• C. 1/2
• D. 1

Answer 1

Answer: (C)

1/2

$r_1=k[A{]}^n$
$r_2=2r_1=k[4A{]}^n$
Divide equation (ii) by (i),
$(2{)}^1=(4{)}^n=(2{)}^{2n}$
$\therefore$ 2n = 1
$n=\frac{1}{2}$