Question

For a chemical reaction, $A\to products$, the rate of reaction doubles when the concentration of A is increased by a factor of 4, the order of reaction is :

• A. 2
• B. 0.5
• C. 4
• D. 1

Answer 1

Answer: (B)

0.5

let x be order of reaction and K be rate of constant.

* A$\to$ products.

$\frac{K\frac{{\left(A\right)}^x}{time}}{K\frac{{\left(4A\right)}^x}{time}}or,\frac{1}{2}={\left(\frac{A}{4A}\right)}^{x}or,\frac{1}{2}={\left(\frac{1}{4}\right)}^x$ (reciprocating)

$or,2={\left(4\right)}^{x}or,2={2^2}^{x}or,2x=1or,x=\frac{1}{2}x=0.5$