For a chemical reaction, $m A ⟶ x B$ , the rate law is $r = k [A]^{2}$ . If the concentration of $A$ is doubled, the reaction rate will be :

doubled

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quadrupled

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increases by

8

times

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unchanged

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Solution

The correct option is B quadrupled
If the concentration of $[A]$ will be doubled rate of reaction will increase four times as rate depends on square of conc. of $A$ i.e. $r = k [A]^{2}$ .

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For a chemical reaction, mA⟶xB, the rate law is r=k[A]2. If the concentration of A is doubled, the reaction rate will be :

The correct option is B quadrupledIf the concentration of [A] will be doubled rate of reaction will increase four times as rate depends on square of conc. of A i.e. r=k[A]2.

For a chemical reaction, $m A ⟶ x B$ , the rate law is $r = k [A]^{2}$ . If the concentration of $A$ is doubled, the reaction rate will be :

The correct option is B quadrupled
If the concentration of $[A]$ will be doubled rate of reaction will increase four times as rate depends on square of conc. of $A$ i.e. $r = k [A]^{2}$ .