wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

For a circle x2+y2=81, what is the equation of chord whose mid-point is (2,3)?

A
2x3y+13=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3x2y+13=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x3y13=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x+3y+13=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2x3y+13=0
Equation of the required chord is T=S
2x+3y9=4+99
2x+3y=4+9
2x3y+13=0.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Radical Axis of Two Circles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon