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Question

For a circular loop of radius 0.02 m, the magnetic flux is 0.5×102 weber. Calculate the strength of the magnetic field around the loop which is perpendicular to the plane of the loop.

A
2 T
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B
3 T
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C
4 T
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D
5 T
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Solution

The correct option is C 4 T
Given: ϕ=0.5×102 weber, r=0.02 m

Since, ϕ=BAcosθ, since θ=0

We get,

B=ϕA=0.5×102π×(0.02)2

B=3.98 T4 T

So, option (c) is the right answer.

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