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Faraday's Experiment

For a circula...

Question

For a circular loop of radius $0.02 m$ , the magnetic flux is $0.5 \times 10^{- 2} weber$ . Calculate the strength of the magnetic field around the loop which is perpendicular to the plane of the loop.

A

2 T

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B

3 T

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C

4 T

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D

5 T

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Solution

The correct option is C $4 T$
Given: $ϕ = 0.5 \times 10^{- 2} weber, r = 0.02 m$

Since, $ϕ = B A cos θ$ , since $θ = 0^{\circ}$

We get,

$B = \frac{ϕ}{A} = \frac{0.5 \times 10^{- 2}}{π \times (0.02)^{2}}$

$B = 3.98 T \approx 4 T$

So, option (c) is the right answer.

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