Question

For a common-emitter transistor, input current is 5$\mu A$, $\beta$ = 100. Circuit is operated at load resistance of 10$k\Omega$. The voltage across collector emitter will be

• A. 5 V
• B. 10 V
• C. 12.5 V
• D. 7.5 V

Answer 1

Answer: (A)

5 V

$I_B=5\mu A$

$I_C=\beta I_B$

$I_C=100\times 5\times {10}^{-6}=0.5mA$

$V_{CE}=I_C{R}_L$

$V_{CE}=5\times {10}^{-4}\times {10}^4$

$V_{CE}=5V$