For a complex number a + ib where b = 0 and a < 0, the argument will be

π

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π

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None

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Solution

The correct option is B $π$
For a + ib if b = 0 and a < 0, the number becomes a negative real number. And we know that for a negative real number the argument is π as it lies on negative x-axis.

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For a complex number a + ib where b = 0 and a < 0, the argument will be

The correct option is B πFor a + ib if b = 0 and a < 0, the number becomes a negative real number. And we know that for a negative real number the argument is π as it lies on negative x-axis.

The correct option is B $π$
For a + ib if b = 0 and a < 0, the number becomes a negative real number. And we know that for a negative real number the argument is π as it lies on negative x-axis.