For a concave lens of focal length f, the relation between object and image distances u and y, respectively, from its pole can best be represented by(u=v is the reference line):
A
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B
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C
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D
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Solution
The correct option is A From lens formula, 1v−1u=1f⇒v=ufu+f
On differentiating lens formula, dvdu=v2u2
Case-I:
If v=u⇒f+u=f⇒u=0 dvdu=v2u2=1
Case-II:
If u=∞ then v=f
Hence, correct u versus v graph, that satisfies this condition is (a).