Question

For a d-electron, the orbital angular momentum is:

• A. $\sqrt{6}\left(\frac{h}{2\pi }\right)$
• B. $\sqrt{2}\left(\frac{h}{2\pi }\right)$
• C. $\left(\frac{h}{2\pi }\right)$
• D. $2\left(\frac{h}{2\pi }\right)$

Answer 1

Answer: (A)

$\sqrt{6}\left(\frac{h}{2\pi }\right)$

We know that the orbital angular momentum (L) $=\sqrt{l(l+1)}\frac{h}{2\pi }$

For $d-orbital,l=2$

Thus, the orbital angular momentum is $=\sqrt{6}\frac{h}{2\pi }$